Steel Buildings in Europe

Title 6.5 Worked Example – Column base 2 of 3 5 – 106 6.1. Base plate size Basic requirement: A p  A req Area of base plate: A p = h p  b p = 600  600 = 360000 mm 2 Design strength of the concrete: f cd = c ck cc   f = 1,5 1, 0 30  = 20 N/mm 2 Area required: A req = jd Ed f N = 1,5 20 3 2 10 4300 3    = 215000 mm 2 Ref [3] f cd from EN 1992-1-1 §3.1.6(1) α cc from EN 1992-1-1 §3.1.6(1)  C from EN 1992-1-1 Table 2.1N A p = 360000 mm 2 > 215000 mm 2 OK 6.2. Calculation of c A eff p f + 2 t c b +2 b p h +2 h t f t w t w +2 c h c b c Basic requirement: A eff = A req To calculate the effective area, assume first that there is no overlap. A eff ≈ 4 c 2 + Per col c + A col Column perimeter Per col = 1771 mm Area of column A col = 16130 mm 2 A eff ≈ 4 c 2 + 1771 c + 16130 = 215000 = A req  c = 93 mm To ensure that there is no overlap, c has to be less than half the depth between flanges: 2 2 f t h  = 2 320 2 20,5   = 139,5 mm > 93 mm Therefore the assumption that there is no overlap is correct.